Minimun wavelegth of balmer series of He2+ spectrum will be
Answers
Answered by
1
Explanation:
Wavelength of photon emitted in Balmer series of Hydrogen atom
λ
1
=R(
2
2
1
−
n
2
1
)
where n=3,4,5,.....
For minimum wavelength n=∞
So,
λ
min
1
=R(
2
2
1
− ∞1
)= 4R
⟹ λ min
= R4
= 1.097×1074
=364.6 nm
Answered by
5
Just see the image
The answer is 364.6nm
Attachments:
Similar questions