Question

Minimun wavelegth of balmer series of He2+ spectrum will be

Answer 1

Explanation:

Wavelength of photon emitted in Balmer series of Hydrogen atom

λ

1

=R(

2

2

1

−

n

2

1

)

where n=3,4,5,.....

For minimum wavelength n=∞

So,

λ

min

1

=R(

2

2

1

− ∞1

)= 4R

⟹ λ min

= R4

= 1.097×1074

=364.6 nm

Answer 2

Just see the image

The answer is 364.6nm