minus 1 by 2 is a zero of the polynomial p multiply y equal to 2y + 1.
Answers
Answer:
Answer:
Step-by-step explanation: so p(x)=1
X^2-3a-1x-1=0
Apply the value of x =1as p(x)=1
So,
1-3a-1-1=0
1-3a-2=0
1-2=3a
-1=3a
A=-1/3
Step-by-step explanation:
Answer:In mathematics, the degree of a polynomial is the highest of the degrees of the polynomial's monomials (individual terms) with non-zero coefficients. The degree of a term is the sum of the exponents of the variables that appear in it, and thus is a non-negative integer. The term order has been used as a synonym of degree but, nowadays, may refer to several other concepts (see order of a polynomial (disambiguation)). For example, the polynomial {\displaystyle 7x^{2}y^{3}+4x-9,}{\displaystyle 7x^{2}y^{3}+4x-9,} which can also be expressed as {\displaystyle 7x^{2}y^{3}+4x^{1}y^{0}-9x^{0}y^{0},}{\displaystyle 7x^{2}y^{3}+4x^{1}y^{0}-9x^{0}y^{0},} has three terms. The first term has a degree of 5 (the sum of the powers 2 and 3), the second term has a degree of 1, and the last term has a degree of 0. Therefore, the polynomial has a degree of 5, which is the highest degree of any term.
To determine the degree of a polynomial that is not in standard form (for example:{\displaystyle (x+1)^{2}-(x-1)^{2}}(x+1)^{2}-(x-1)^{2}), one has to put it first in standard form by expanding the products (by distributivity) and combining the like terms; for example {\displaystyle (x+1)^{2}-(x-1)^{2}=4x}(x+1)^{2}-(x-1)^{2}=4x is of degree 1, even though each summand has degree 2. However, this is not needed when the polynomial is expressed as a product of polynomials in standard form, because the degree of a product is the sum of the degrees of the factors.