Question

MINUT)
ut f(x) = f(2) ► 2a+b=4
x2+
Lt f(-x) = f(5) ► 5 a+b = 13
x-
3 a = 9 or a=3
from (1), 6+ b =4 → b= -2
a = 3, b=-2
EXERCISE 5 (4)
x2 +3, if **
Show that the function f given by f(x)
1, if x=0,
is not continuous at x = 0..
Subtracting (1) from (2), we get​

Answer 1

Answer:

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