Question

minute hand of clock is 10 cm long find the average speed of its tip from 3.00 pm to 3.15pm​

Answer 1

Answer:

Between 6 am to 6:30 am

Average speed = Total distance/ Time

= πr / (30 × 60 seconds)

= 4π/1800

= 0.00698 cm/s

Average velocity = Total displacement/ Time

= 2r / (30 × 60 seconds)

= 9 / 1800

= 0.005 cm/s

Average velocity and average speed between 6 am to 6:30 pm is same as that of 6 am to 6:30 am

Answer 2

Answer:

Thus, the speed of the tip is $0.017cm/s$.

Explanation:

Concept:

According to this query, a minute hand clock with a $10$ cm length exists. And from $3:00$ to $3:15$, we need to determine the average speed of its tip. means that we are at $15$ minutes.

Given:

The length of minute hand clock $=10 cm$

To find:

We have to calculate the average speed of its tip from $3:00$ to $3:15$.

Solution:

Given that the minute hand's length in this instance is $10$ cm and that it goes from $3:00$ to $3:15$, we know that the angle between those two times is $90$°.

As we know that ,

length of arc $= r\theta$[where $\theta$ is in radians].

Since $\theta$ is in degrees, we need to convert it into radians,

$90$° $= 180 /2$

$=\frac{\pi}{2} as (180=\pi )$

length of arc $= 10* \frac{\pi }{2}$

length of arc $= 5\pi$

And here the time between $3:00$ to $3:15$ is $15$ min,

So now converting minutes into seconds,

$15mins = 900s$

Now , $speed = \frac{distance}{time}$

Speed $= \frac{5\pi}{900}$

Speed $= \frac{\pi}{180}$

Speed $= 0.017 cm/s$

Therefore, the speed of its tip $= 0.017cm/s$ .

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