minute hand of clockis 10cm find area of face of clock described by minute hand between9am and 9.35am
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radius=10cm
area swept by minute hand is 35mins(9to9:35)
so angle described by minute hand in 35 mins ,theta =210 degrees (for 35mins 360/60 ×35 =210 degrees)
so area swept in 35 min =πr ² theta/360
=22/7 ×10×10×210/360
=550/3
=183 1/3 ( it is in mixed fraction)
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area swept by minute hand is 35mins(9to9:35)
so angle described by minute hand in 35 mins ,theta =210 degrees (for 35mins 360/60 ×35 =210 degrees)
so area swept in 35 min =πr ² theta/360
=22/7 ×10×10×210/360
=550/3
=183 1/3 ( it is in mixed fraction)
mark this answer brainliest
Answered by
1
Hey!
_______________________________
Solution-:
Radius = 10cm
Area swept by minute hand= 35 min
We know,
60 minutes= 360°
1 minute = 360/60 = 6°
35 min= 35×6= 210°
Area swept in 35 minutes= πr^2 θ/360
= 3.14×10×10×60/360
= 550/3 m^2
_______________________________
Hope it helps...!!!
_______________________________
Solution-:
Radius = 10cm
Area swept by minute hand= 35 min
We know,
60 minutes= 360°
1 minute = 360/60 = 6°
35 min= 35×6= 210°
Area swept in 35 minutes= πr^2 θ/360
= 3.14×10×10×60/360
= 550/3 m^2
_______________________________
Hope it helps...!!!
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