Math, asked by jugrajsingh10101983, 4 days ago

Mira has a circular cardboard with centre 0. The cardboard has been divided into three regions labelled X, Y and Z by diameter AB and radius OC as shown in the following figure. She places a fair spinner at the centre of the cardboard. If ∆BOC = 45° answer each of the following questions:
1. the probability that the spinner will land in the region x, is
a. 1/4 b) 1/2 c) 1/8 d) 3/8

2. the probablity that the spinner will land in the region y, is
a) 1/4 b) 1/2 c) 1/8 d) 3/8

3. the probability that the spinner will land land in the region z is
a) 1/4 b) 1/2 c) 1/8 d) 3/8


4. the probability that the spinner will land in the region x Or z is
a) 1/4 b) 1/2 c) 1/8 d) 3/8


5. the probabilty that the spinner will land in the region y Or z is
a) 3/8 b) 1/2 c) 5/8 d) 1/8​

Answers

Answered by kiratikaravi
1

Step-by-step explanation:

R=3cm, H=10.5cm

⇒Surface area = Curved Surface Area + Base Area

=2πrh+πr

2

=2×

7

22

×3×

10

10.5

+

7

22

×3×3cm

2

=198+

7

198

cm

2

=

7

1584

cm

2

⇒Area of cardboard sheet used by competitor =

7

1584

cm

2

⇒Area of cardboard sheet used by 35 competitors =

7

1584

×35

=7920cm

2

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