Physics, asked by minhazalam82, 11 months ago

mirror forms and erect image 30 cm from the object and twice its height where the mirror must be situated what is the radius of curvature​

Answers

Answered by Sakshihhimanshu
1

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Answered by Dhirajmehta854
0

Answer:below

Explanation:

Let the image formed is virtual and erect.

V – u = 30 cm

m = 2

(a) m = - (v/u)

2 = - (v/u)

V = -2u

-2u – u = 30 cm

u = -10 cm

(b) v = -2u = 20 cm

1/v + 1/u = 1/f

1/20 + 1/-10 = 1/f

1/f = -1/20

f = -20 cm

R = 2f = -40 cm

(c) Concave mirror

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