mirror forms and erect image 30 cm from the object and twice its height where the mirror must be situated what is the radius of curvature
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Explanation:
Let the image formed is virtual and erect.
V – u = 30 cm
m = 2
(a) m = - (v/u)
2 = - (v/u)
V = -2u
-2u – u = 30 cm
u = -10 cm
(b) v = -2u = 20 cm
1/v + 1/u = 1/f
1/20 + 1/-10 = 1/f
1/f = -1/20
f = -20 cm
R = 2f = -40 cm
(c) Concave mirror
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