mirror formula class 10th
chhavi056:
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Answered by
35
A formula which gives the relationship between image distance (v),object distance(u), and focal length(f) of a spherical mirror is known as the mirror formula .
Mirror formula can be written as:
where,
v= distance of image from mirror
u= distance of object from mirror
f= focal length of the mirror
The distance of an object from the pole of mirror is known as object distance. object distance is denoted by the letter u.
The distance of image from the pole of a mirror is known as image distance. image distance is denoted by the letter v.
The distance of focus from the pole of a mirror is known as focal length. focal length is denoted by the letter f.
Mirror formula can be written as:
where,
v= distance of image from mirror
u= distance of object from mirror
f= focal length of the mirror
The distance of an object from the pole of mirror is known as object distance. object distance is denoted by the letter u.
The distance of image from the pole of a mirror is known as image distance. image distance is denoted by the letter v.
The distance of focus from the pole of a mirror is known as focal length. focal length is denoted by the letter f.
Answered by
25
Hey mate ^_^
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Answer:
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In Triangles BAC and A’B’C'
AB/A’B’ = CB/CB’ - - - - - (i)
Now,
Triangle ABP and A’B’P’ are similar,
AB/A’B’ = PB/PB’ - - - - - (ii)
From (i) & (ii)
CB/CB’= PB/PB’ - - - - - - (iii)
Measuring all distances from P,
We have,
CB= PB-PC CB’= PC-PB’
Therefore from (iii),
(PB-PC)/(PC-PB’) = PB/PB’ - - - - - (iv)
Using new cartesian sign convections,
PB= -u (distance of object)
PC= -R PB’ = -v (distance of image)
We get from (iv),
uR + vR = 2uv
Dividing both sides by uvR,
We get,
1/v + 1/u = 2/R
R=2f
Therefore,
1/v + 1/u = 2/R = 2/2f = 1/f
This is the required formula.
#Be Brainly❤️
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Answer:
=======
In Triangles BAC and A’B’C'
AB/A’B’ = CB/CB’ - - - - - (i)
Now,
Triangle ABP and A’B’P’ are similar,
AB/A’B’ = PB/PB’ - - - - - (ii)
From (i) & (ii)
CB/CB’= PB/PB’ - - - - - - (iii)
Measuring all distances from P,
We have,
CB= PB-PC CB’= PC-PB’
Therefore from (iii),
(PB-PC)/(PC-PB’) = PB/PB’ - - - - - (iv)
Using new cartesian sign convections,
PB= -u (distance of object)
PC= -R PB’ = -v (distance of image)
We get from (iv),
uR + vR = 2uv
Dividing both sides by uvR,
We get,
1/v + 1/u = 2/R
R=2f
Therefore,
1/v + 1/u = 2/R = 2/2f = 1/f
This is the required formula.
#Be Brainly❤️
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