mirror image of (-2,-11) on y axis
Answers
Answer (-4,2) lies in II quadrant i.e, 2 units above the x-axis.
(i) ∴ image B of a point A(-4,2) in x-axis will be just below the x-axis i.e. in III quadrant. So, image B=(−4,−2).
Since, (-4,2) lies in II quadrant i.e., 4 units left to the y-axis.
∴ Image C of a point A(-4,2) in y-axis will be just right to the y-axis i.e, in I quadrant. so, image C=(4,2).
If (x,y) be any point then its image in the origin will be (−x,−y) i.e., image will be in the opposite quadrant.
Here, (-4,2) lies in II quadrant, so its image D will be in IV quadrant.
∴ Image D=(4,−2)
Since AB=CD=2+2=4 units
and AC=BD=4+4=8 units
∴□ACDB is a rectangle whose length AC=8 units and breadth CD=4 units In right triangle ACD.
Now, by Pythagoras theorem AD2=AC2=CD2
=(8)2+(4)2
=64+16
=80
∴AD=80−−√units
⇒AD=45–√ units
Answer:
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