Question

mis moving towards a player with velocity v. If player stopped it, then impulse applied by the
player is
(1) – mv
(3) – 2 m
(2) + mv
(4) + 2 mv


please give answer​

Answer 1

Correct Question—

A ball of mass m is moving towards a player with velocity v. If player stopped it, then impulse applied by the player is

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✍ (1) —mv

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EXPLANATION —

Let 'a' be the retardation of the ball

u₀ = u + at

=> 0 = v + at

=> t = -v/a

where t = Δt , time for which 'a' is acting.

FΔt = ma × -v/a = -mv

Hence, the impulse applied by the player would be -mv.

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Answer 2

Answer is in the attachment attached below.