Question

Miscellaneous factorizations
6. Factorize:
(a)(x + 1) ² + x - 5
​

Answer 1

Step-by-step explanation:

(x+1)^2+x-5

=x^2+2x+1+x-5

=x^2+3x-4

=x^2+4x-x-4

=x(x+4)-1(x+4)

=(x+4)(x-1)

Answer 2

Answer:

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Step-by-step explanation:

$(x + 1) ² + x - 5$

$[using \: (a+b)² = a² + 2ab+b²]$

$=> x²+2x+1+x-5$

$= x²+3x-4$

$now, solving \: this \\ by \: quadratic \: formula , we \: get :$

$Here , \: a = 1 , \: b = 3 , \: c = -4$

$D = b²-4ac$

$= (3)²-4(1)(-4)$

$= 9+16$

$= 25$

$Now , \: x = -b ±√D/2a$

$= -3±√25/2$

$= -3+5/2 \: \: \: \: , \: -3-5/2$

$= x = 1 , -4$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

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