Question

miss find the largest positive interger that will divide 122,150 and 115 leaving remainder 5,7 and 11 respectively

Answer 1

$\huge{\boxed{\boxed{\mathtt{\red{QuEsTiOn}}}}}$

find the largest positive interger that will divide 122,150 and 115 leaving remainder 5,7 and 11 respectively.

$\huge{\underline{\underline{\mathfrak{\blue{Given \::--}}}}}$

The Numbers122,150 and 115 .

$\huge\underline\purple{\sf To FinD:-}$

A positive interger that will divide 122,150 and 115 leaving remainder 5,7 and 11 respectively.

$\huge{\boxed{\boxed{\mathtt{\green{Answer:-}}}}}$

$\longrightarrow$$122 - 5 = 117$

$\longrightarrow$$150 - 7 = 143$

$\longrightarrow$$115 - 11 = 104$

$\longrightarrow$Hence, The common factor between 117,143 & 104 is 13.

$\longrightarrow$So we can say that, the positive integer which can divide the 122,150 and 115 leaving remainder 5,7 and 11 respectively is 13

$\huge{\boxed{\boxed{\mathtt{\red{ThanKs}}}}}$

Answer 2

$\huge\boxed{\fcolorbox{cyan}{orange}{ANSWER!!...}}$

$\huge\underline\mathit\blue{given!!...}$

120, 150, and 115 are positive integers...

$\huge\underline\mathit\blue{to\:find!!...}$

a largest positive interger that will divide 122,150 and 115 leaving remainder 5,7 and 11 respectively...

$\huge\underline\mathit\blue{solution!!...}$

• •122 - 5 = 117

• •150 - 7 = 143

• •115 - 11 = 104

NOW TAKE THE HCF :

--- 117 = 3 × 3 × 13

--- 143 = 11 × 13

--- 104 = 2 × 2 × 2 × 13

$\green{\underline\textbf{HCF = 12}}$

$\red{\underline\textbf{hence, the common factor between 122,150 and 115 is 13...}}$

hope!!...it helps uhh...✌️❣️