Question

Missing Number in the series 1, 9, ?, 49, ?, 121
Complete in the below series : 1, 9, ?, 49, ?, 121

Answer 1

25 and 81 respectively because 5^2 and 9^2. There is a difference of 2 between the square root of the numbers in the series and the numbers required will be the square of the numbers. The numbers will be 1,3,5,7,9,11. Their squares are 1,9,25,49,81,121.

Answer 2

The missing terms are 25 and 81.

Given:

Series: 1, 9, ?, 49, ?, 121

To find:

The missing terms

Solution:

We can obtain the required terms by determining the pattern in the given series.

Let the missing terms be X and Y.

The series: 1, 9, X, 49, Y, 121

We see that the given terms are the squares of the first 6 odd natural numbers.

The first 6 odd natural numbers are 1, 3, 5, 7, 9, and 11.

$1^{2}$=1

$3^{2}$=9

X=$5^{2}$=25

$7^{2}$=49

Y=$9^{2}$=81

$11^{2}$=121

The series= 1, 9, 25, 49, 81, 121

Therefore, the missing terms are 25 and 81.

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