Question

missing term 5,13,40,104,229,?
a) 475
b) 445
c) 296
d) 180
solution:
to find misiing term in above series
5,13,40,104,229,?------(1)
differnce between numbers in the series
13-5=8,40-13=27,104-40=64,229-104=125
8,27,64,125-----(2)
these above series we can written as
2^3,3^3,4^3,5^3,6^3
from 1 d 2
5+8=13
13+27=40
40+64=104
104+125=229
next 6^3 is 216+229=445
ans is 445

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Answer 1

Answer:

445 is correct answer

thank for giving points

Answer 2

Answer:

b) 445 is the answer

Step-by-step explanation:

solution:

to find misiing term in above series

5,13,40,104,229,?------(1)

differnce between numbers in the series

13-5=8,40-13=27,104-40=64,229-104=125

8,27,64,125-----(2)

these above series we can written as

2^3,3^3,4^3,5^3,6^3

from 1 d 2

5+8=13

13+27=40

40+64=104

104+125=229

next 6^3 is 216+229=445

ans is 445

hope it works!!!

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