Physics, asked by govind9981, 9 months ago

mistake percentage of a 1%b2%c3%d4% x= A²-B½/C¼-D² find the value of X​

Answers

Answered by Anonymous
12

Answer:

\displaystyle{Error \ \% \ in \ x=11.75\%}

Explanation:

Given percent error ;

A = 1 %

B = 2 %

C = 3 %

D = 4 %

\displaystyle{x=\dfrac{A^2-B^{1/2}}{C^{1/4}-D^2}}\\\\\\\displaystyle{Error \ \% \ in \ x=2\left(\dfrac{\Delta A}{A}\times100\right)+1/2\left(\dfrac{\Delta B}{B}\times100\right)+1/4\left(\dfrac{\Delta C}{C}\times100\right)+2\left(\dfrac{\Delta D}{D}\times100\right)}\\\\\\\displaystyle{Error \ \% \ in \ x=2\times1\%+1/2\times2\%+1/4\times3\%+2\times4\%}\\\\\\\displaystyle{Error \ \% \ in \ x=2\%+1\%+0.75\%+8\%}\\\\\\\displaystyle{Error \ \% \ in \ x=11.75\%}

Thus we get answer .

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