mitra redesigns a box of length 20cm width 30 cm height 40cm to a box of height 50cm if the new box has same volume and length as the original box find the width of the new box
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ht. of old box = 40cm
ht. of new box = 50 cm
breadth of old box = 30cm
breadth of new box = (to be calculated)
length of old box = 20cm
length of old box = length of new box. (given)
since this box is like a cuboid
so,volume of cuboid = l×b×h
= 24000cm(cube)
according to condition
volume of old box = volume of new box
24000 = L×B×H
24000 = 20 × 50 × B
24000/1000 = B
24 = B
hence Breadth ( width ) of new box
= 24 cm
plzzzzz. mark it as Brainlist
ht. of new box = 50 cm
breadth of old box = 30cm
breadth of new box = (to be calculated)
length of old box = 20cm
length of old box = length of new box. (given)
since this box is like a cuboid
so,volume of cuboid = l×b×h
= 24000cm(cube)
according to condition
volume of old box = volume of new box
24000 = L×B×H
24000 = 20 × 50 × B
24000/1000 = B
24 = B
hence Breadth ( width ) of new box
= 24 cm
plzzzzz. mark it as Brainlist
sunny640:
plz mark it as brainlist
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