Mixture A contains only liquid X and liquid Y while mixture B contains 80% liquid X, 4% liquid Yand 16
liquid Z. If both the mixtures are mixed to get a new mixture having 74% liquid X, 16% liquid Yand 10%
liquid Z then find the ratio in which mixture A and mixture B is mixed to get that new mixture?
1.56
2.3:2
3 3.2:
4 .3: 5
5.5:7
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3: 5 is the ratio in which mixture A and mixture B is mixed to get that new mixture
Step-by-step explanation:
Let say Liquid A mixed has C litre X liquid
& D litre Y liquid
Total Mixture = C + D litre
Mixture B mised is E litres
X - 0.8E , Y = 0.04E Z = 0.16E
Total C + D + E
X = 0.74(C + D + E) = C + 0.8E
Y = 0.16(C + D + E) = D + 0.04
Z = 0.1(C + D + E) = 0.16E => 0.1(C + D) = 0.06E
=> C + D = 0.6E
=> C + D = 6E/10
=> (C + D)/E = 6/10
=> (C + D)/E = 3/5
3: 5 is the ratio in which mixture A and mixture B is mixed to get that new mixture
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