Question

Mixture A contains only liquid X and liquid Y while mixture B contains 80% liquid X, 4% liquid Yand 16
liquid Z. If both the mixtures are mixed to get a new mixture having 74% liquid X, 16% liquid Yand 10%
liquid Z then find the ratio in which mixture A and mixture B is mixed to get that new mixture?
1.56
2.3:2
3 3.2:
4 .3: 5
5.5:7​

Answer 1

3: 5 is the ratio in which mixture A and mixture B is mixed to get that new mixture

Step-by-step explanation:

Let say Liquid A  mixed has   C litre  X  liquid

& D  litre   Y liquid

Total Mixture = C + D  litre

Mixture B  mised is   E  litres

X - 0.8E  , Y  = 0.04E   Z = 0.16E

Total C + D  + E

X = 0.74(C + D + E)  = C  + 0.8E

Y  = 0.16(C + D + E) = D  + 0.04

Z = 0.1(C + D + E)  = 0.16E       => 0.1(C + D) = 0.06E

=> C + D = 0.6E

=> C + D = 6E/10

=> (C + D)/E  = 6/10

=> (C + D)/E = 3/5

3: 5 is the ratio in which mixture A and mixture B is mixed to get that new mixture

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