Question

mixture is 3:4,if the mixture contains 6MG of substance A, how much is there in substance B

Answer 1

Answer:

Substance B is 8mg

Step-by-step explanation:

Ratio= 3:4

let the substance A= 3x = 6mg (given)

then, substance B= 4x

now,

3x = 6

x = 6/3

x= 2

then,

Substance B = 4x = 4×2 = 8

Substance B = 8mg

Answer 2

Answer:

B has 8 milligrams

Step-by-step explanation:

3:4 can be written as $3x:4x$

thus, $3x=A$

and  $4x = B$

$3x = 6mg; \\x= \frac{6}{3} \\\x = 2$

now using this we can find how much is there in substance B

by,

4x = B

so, 4×2 = B

8mg = B