Question

mixture of 20 L of milk and water contains 20% water
How much water should be added to this mixture so that
the new mixture contains 25%
water?
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Answer 1

Answer:

your answer is 1.34 litres approx.

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Explanation:

$\huge \red { \underline { \underline {answer}}} \colon \\ amount \: of \: water \: mixed = \frac{ \cancel{20}}{ \cancel{100}} \times \cancel {20}l \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 4l \\ let \: amount \: of \: water \: to \: be \: mixed \: in \: milk \: to \: be \: x \: litres now \\ \implies (4 + x) = 25\% \: of \: (20 + x) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ (20 + x \: is \: new \: amount \:of \: mixture \: \\ after \: adding \: water \: to \: it) \\ \implies4 + x = \frac{25}{100} \times (20 + x) \\ \implies 4 + x = \frac{500 + 25x}{100} \\ \implies100(4 + x) = 500 + 25x \\ \implies400 + 100x = 500 + 25x \\ \implies100x - 25x = 500 - 400 \\ \implies75x = 100 \\ \implies \: x = \frac{ \cancel{100}}{ \cancel{75} } \\ \implies \: x = 1.34 \: litres \: approx. \\ 1.34 \: litres \: approx. \: should \: be \: added \: to \: have \: 25\% \: of \: water \: in \: mixture \\ \huge \: \: \: \: \: \: \: \: \: \: \: \: \downarrow \downarrow\downarrow\downarrow\downarrow \\ \\ \\ \huge \orange{hope \: it \: help \: you } \\ \huge plese \: mark \: as \: brainliest \\ \huge \green {have \: a \: nice \: day}$