mixture of 30 pounds of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates worth 90¢ a pound. How many pounds of the $1.50 chocolate were used to make the mixture?
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Let required no of pounds of chocolates($1.10 a pound) be x.
∴The no of pounds of chocolates worth 90¢ a pound is (30-x).
∴1.5*x+0.9*(30-x) = 1.1*30 [ ∵Total price of the mixture = $(1.1*30)]
Solving, we get,
x=10
∴Required no of chocolates worth $1.50 a pound is 10 pounds.(Ans.)
∴The no of pounds of chocolates worth 90¢ a pound is (30-x).
∴1.5*x+0.9*(30-x) = 1.1*30 [ ∵Total price of the mixture = $(1.1*30)]
Solving, we get,
x=10
∴Required no of chocolates worth $1.50 a pound is 10 pounds.(Ans.)
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