Question

Mixture of ethanol and acetone shows positive deviation from Raoult’s Law

Answer 1

Molecules of ethanol in pure state are hydrogen bonded. But when acetone is added to the ethanol, molecules of acetone get in between the molecules of ethanol and break some of the hydrogen bond, which weaken the intermolecular attractive forces resulting in increase in vapour pressure of mixture than ethanol in pure state.

Because of this mixture of ethanol and acetone shows positive deviation in vapour pressure from Raoult’s Law.

Answer 2

Mixture of ethanol and acetone shows positive deviation from Raoult’s Law

Solution:

The result that comes is cyclohexanol and ethanol. In the ethanol by the strong bonds are generally held by the hydrogen and when cyclohexanol is added to the solution of ethanol they have the tendency to space up between the atoms due to which the hydrogen bonds break. Gradually the ethanol turns into vapour and become light weight.