Question

mixture of pure AgCl and AgBr contains 60.94%Ag by mass . what is % of AgCl?

Answer 1

The fraction of silver in each of the compounds is:

Ag/AgCl = 0.7529

Ag/AgBr = 0.5746

The fraction of silver in the mixed sample is 0.6094 therefore, if we let x = the fraction of the sample that is AgCl and (1-x) is the fraction of the sample that is AgBr, then:

x(0.7529) + (1-x)(0.5746) = 0.6094

Solving for x:

x = 0.1949 or 19.49% AgCl in the sample.