Question

Mixture of two bivalent metal A and B having
mass 2g when dissolved in HCl at STP, 2.24 L
He is evolved. What is the mass of A present in
mixture?
(Atomic mass of A= 15 u, B = 30 u)​

Answer 1

Answer:

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Answer 2

A+2HCl→ACl2+H2A+2HCl→ACl2+H2

mole =x15=x15

B+2HCl→BCl2+H2B+2HCl→BCl2+H2

mole =2−x30=2−x30

mole ofH2

=x15+2−x30=2.2422.4

=110ofH2=x15+2−x30

=2.2422.4=110

x15−x30=110−115x15−x30=110−115

x=1gm