Question

Miya thinks of a number and subtracts 8/5

from it. She multiplies

the result by 10. The result now obtained is 6 times the same

number she thought of. What is the number​

Answer 1

Given:

she subtract 8/5 from it

i.e. x-8/5

and multiply result by 10

new number =10(x-8/5)

$10\left(x-\frac{8}{5}\right)=6 x$

$10 x-10 \times \frac{8}{5}=6 x$

10x-16=6x

10x-6x=16

4x=16

x=16/4

x=4

Hence the miya number thought is 4

Answer 2

Answer:

to find : original number

let the number thinks be ' x' , then according to question we have

$(x - \frac{8}{5} ) \times 10 = 6x$

new number = $(x-\frac{8}{5} )\times 10$   $= 6x$

$10x - 16 =6x$

$4x = 16$

$x = \frac{16}{4}$

$x = 4$

hence the number she thought was 4.

 

 

 

 

Hence the miya number thought is 4

hence the number she thought was 40.