ML^-1T^-2 × l^3 is equal to
Answers
Answered by
0
Answer:
ANSWER
Pressure P= force/ area =F/A
[P]=[MLT
−2
]/[L
2
]=[ML
−1
T
−2
]
Energy per unit volume , E= work done/volume =(force ×displement)/volume
[E]=
[L
3
]
[MLT
−2
][L]
=[ML
−1
T
−2
]
The dimension of force, [F]=[MLT
−2
] and linear momentum, [p]=[mv]=[MLT
−1
]
Explanation:
please mark me as brainlest and follow ,me
Answered by
0
Answer:
ML^2T^-2
Explanation:
=M×T^-2×L^-1×L^3
=MT^-2×L^-1+3
(Bez in multiplication powers are added)
=MT^-2L^2(This is dimenssion of energy)
Its unit is joule.
Similar questions