Question

___________ml of KOH is required to prepare 100ml of 1% KOH solution from 5% KOH solution

1 point

5ml

10ml

20ml

3oml


​

Answer 1

Answer:

Molarity=

GMW of KOH

Weight of KOH

×

Vol(ml)

1000

[GMW of KOH= Atomic weight of K+ atomic weight of O+ atomic weight of H=10+16+1=27]

⇒0.1=

27

Weight of KOH

×

100

1000

Weight of KOH=

10

2.7

Weight of KOH=0.27 g