Question

MLT-2] matches with the dimensional formula of ____

a) Force

b) Modulus of elasticity

c) Displacement

d) Strain​

Answer 1

Answer:

displacement-m/s

force- f=ma

modulus of elasticity=σ2 - σ1) / (ε2 - ε1) where stress (σ) is force divided by the specimen's cross-sectional area and strain (ε) is the change in length of the material divided by the material's original gauge length.

.xD

Answer 2

Answer:

Option A is the right option.

Explanation:

Dimensional formula refers to the expression that represents any physical quantity in terms of base quantities.

Part A:

Dimensional Formula of Force,

$Force=M^{1} L^{1} T^{-2}$

Hence, option A is the right option.

Part B:

Dimensional Formula of Modulus of elasticity,

$Modulus\ of\ elasticity=M^{1} L^{-1} T^{-2}$

Hence, option B is not the right option.

Part C:

Dimensional Formula of Displacement,

$Displacement=M^{0} L^{1} T^{0}$

Hence, option C is not the right option.

Part D:

Dimensional Formula of Strain,

$Strain=M^{0} L^{0} T^{0}$

Hence, option D is not the right option.