mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
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krish02:
answer is one
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b^y=c becomes (a^x)^y=c when we substitute b value , so a^xy=c , now substituting this in third equation , (a^xy)^z=a or in simple terms a^xyz=a , anything raised to 1 is same values , so xyz must be 1 , so that a^1=a , Answer is xyz=1
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