Question

(mn-4x)^2-2m^2n^2 in algebraic identity​

Answer 1

In the given algebraic expression

${2m}^{2} {n}^{2}$

we substitute m=3 and n=2 as shown below:

${2m}^{2} {n}^{2}$

$2 \times ({3}^{2}) \times {2}^{2}$

=2×9×4

=72

$hence {2m}^{2} {n}^{2} = 72$

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Answer 2

Answer:

In the given algebraic expression

{2m}^{2} {n}^{2}2m

2

n

2

we substitute m=3 and n=2 as shown below:

{2m}^{2} {n}^{2}2m

2

n

2

2 \times ({3}^{2}) \times {2}^{2}2×(3

2

)×2

2

=2×9×4

=72

hence {2m}^{2} {n}^{2} = 72hence2m

2

n

2

=72

thanks please mark brainlist