Question

MN is the diameter of a circle with the center 0.If BD=CD, prove that angle OAD =angle OCD.

Answer 1

$\huge\red{\mathbb{\underline{\underline{\underline{HOLA\:NANDINI!!}}}}}$

$<b><i>Join AC.$

On joining AC , we will find that the triangles AOD and COD lies on the same base OD and between the same parallel lines.

Therefore, we can conclude that

area of triangle AOD is equal to area of triangle COD.

We know that triangkes equal in area are congruent.

Therefore,

ANGLE OAD =ANGLE OCD.

$<marquee>hope it helps!!$

$\huge\red\mathfrak{THANKS!}$

Answer 2

On joining AC , we will find that the triangles AOD and COD lies on the same base OD and between the same parallel lines.

Therefore, we can conclude that

area of triangle AOD is equal to area of triangle COD.

We know that triangkes equal in area are congruent.

Therefore,

ANGLE OAD =ANGLE OCD.

hope this answer helpful u