Question

MN O2 + 4 HCL gives twice to mncl 2 + 2 H2O + cl2 in the above equation name the compound which are oxidized and which are the reduced

Answer 1

MnO2 + 4HCl → MnCl2 + Cl2 + 2H2O

Here, Mn is in +4 oxidation state in MnO2 while it is in +2 Oxidation state in MnCl2 , thus a decrease in oxidation no. shows that MnO2undergo reduction, and so it will work as an oxidizing agent.

Similarly, in HCl, Chlorine is in -1 oxidation state while it becomes 0 in Cl2 , the increase in oxidation no. shows that HCl undergoes oxidation and so it will act as a reducing agent.


Substance oxidized : HCl

Substance reduced : MnO2

Oxidizing agent: : MnO2

Reducing agent : HCl

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Answer 2

Explanation:

this is the correct answer