Question

MN parallel to QR if PM. is equal to 1 centimetre, and q is equal to the centimetre, P N is equal to x minus 2 cm and R is equal to 6 cm find x ​

Answer 1

Given,

BC║PQ
BC = 8 cm, PQ = 4 cm, BA = 6.5 cm, and AP = 2.8 cm
We need to find:
CA and AQ

Solution

Since, BC║PQ
   BAC = PAQ                   (vertically opp angles)
   ABC = PQA                   (alternate angles)
   ACB = QPA                    (alternate angles)
By AAA criterion
   ΔABC = ΔPQA   
By BPT,
BA/AQ=CA/AP=BC/PQ
Therefore,
6.5/AQ=8/4
AQ = 6.5×4/8
AQ = 3.25 cm
Similarly,  CA/AP=BC/PQ
CA/2.8=8/4
CA = 2.8 x 2
CA = 5.6 cm
Therefore, CA = 5.6 cm and AQ = 3.25 cm.

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