MN2+ (aq) MnO4 (aq) (acidic solution).
gm
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pMnO4−(aq)+qI−+xH2O(l)→rMnO2(s)+sI2(s)+yOH−(aq)
in a balanced chemical reaction number of all atoms at right side should be equal to the left side of the reaction.
Balancing a chemical reaction as:
Step 1: Assign oxidation numbers to each of the atoms in the equation and write the numbers above the atom as:
Mn+7O4−(aq)+I−−1+H2O(l)→Mn+4O2(s)+I20(s)+OH−(aq)
Step 2: Identify the atoms that are oxidized and those that are reduced as:
Reduction: Mn+7O4−(aq)→Mn+4O2(s)
Oxidation: I−−1→I20(s)
Step 3: oxidation-number change is:
Reduction: Mn+7O4−(aq)→Mn+4O2
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Answer:
MN2+ (aq) MnO4 (aq) (acidic solution).
gm
was it true??!!! the recent question..
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