MnO2(s) + 4 HCl(aq) → MnCl2(aq) + 2 H2O(g) + Cl2(g)
How much HCl (in grams) needs to react with MnO2 to produce 91.50 g of Cl2?
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368 GM's of HCl require to produce it
twm2208:
the program i have to use said the answer was 188.2 but thanks for trying
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