Question

mnop is a rectangle with sides 24m and 16m. the two triangles NOR and triangle MPQ are congruent and rupees 1 no. If the length of rupees. 6.5 m, find the area of he shaded region. ​

Answer 1

Answer:

Area of the shaded region $=280 m^2$

Step-by-step explanation:

Area of the shaded region:

= Area of Rectangle MNOP - Area of ΔMPQ - Area of ΔNOR

= MP . OP - 2 Area of ΔNOR  [∵ ΔMPQ and ]ΔNOR are congruent]

= 16 x 24 $m^2$ $-2.\frac{1}{2}.ON . RS$  

= 16 x 24 $m^2$ $-(16) . (6.5) m^2$

$=16(24-6.5) m^2$

$=16.(17.5) m^2$

$=16.\frac{175}{10} m^2$

$=(8).(35) m^2$

$=280 m^2$

Answer 2

Answer:

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