Question

MNOP is a trapezium in Which MN is parallel to PO , PN is a diagonal and Q parallel to MN intersecting NO in R. Show that R is the mid point of NO

Answer 1

The bisectors of ∠P and ∠Q meet at point A. ∠S = 50° and ∠R = 110°, find ... ∠P = ∠R [Opposite angles of a parallelogram are equal.] ... AB = 12 cm and MN = 14 cm

Answer 2

Answer:

R is the mid point of NO

Step-by-step explanation:

Explanation :

Given , MNOP is a trapezium in which

MN || PO and PN is a diagonal .

Step 1:

QR parallel to MN given in the question

Let QR intersect  PN at G

So ,we have  QG || MN

Therefore G will be the mid point of PN

Step2:

Now ,we have  QR||MN and MN || PO

∴QR|| PO

In ΔNOP , GR || PO

Therefore , R is the mid point of NO.

Final answer:

Hence , here we proved that R is the mid point of NO.