ΔMNT~ΔQRS. Length of altitude drawn from point T is 5 and length of altitude drawn from point S is 9. Find the ratio A(ΔMNT)/A(ΔQRS)
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8
25:81 will be the answer
Answered by
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Answer:
A(ΔMNT)/A(ΔQRS) = 25/81
Step-by-step explanation:
ΔMNT~ΔQRS. Length of altitude drawn from point T is 5 and length of altitude drawn from point S is 9
ΔMNT ≅ ΔQRS
MN/QR = NT/RS / TM/SQ
Altitude drawn would also be in similar ration
so MN/QR = 5/9 - eq 1
Area of ΔMNT = (1/2) MN * 5
Area of ΔQRS = (1/2) QR * 9
Area of ΔMNT/Area of ΔQRS = ( (1/2) MN * 5 ) / ( (1/2) QR * 9)
= (MN/QR)(5/9)
putting value of MN/QR from eq 1
= (5/9)(5/9)
= 25/81
A(ΔMNT)/A(ΔQRS) = 25/81
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