MO
If the length ibreadth depth of the
Cubold is 19 cm. and its diagonal is v5cm
and then its surgace area is.
.
Answers
Answered by
0
Answer:
the surface area = 6 ( lh + bh +lb )
= 6(19×19+19×19+19×19)
=6(361+361+361)
= 6×1083= 2888 sq. cm
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