mo) If the velocity of an object moving with uniform acceleration changes from 20m/s to 40 m/s in 5 seconds,
a. What is the acceleration of the object? b. What is the displacement of the object during this time interval?
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Answer:
No,because if the moving object comes back to its initial position the distance travelled is not zero.
Though the moving object comes back to its initial position the distance travelled is not zero.
Displacement is calculated on the basis of initial and final position. If initial and final position are same, displacement is zero. But distance is the total distance covered from initial to final position. So, it cannot be zero in this case.
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a) finding Acceleration of the object :
a = (v - u)/t
so,
⇒ a = (40-20)/5
⇒ a = 20/5 = 4 m/s²
- Acceleration of the object = 4 m/s²
b) Displacement during time interval :
s = v - u
⇒ s = 40-20 = 20m
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