Question

mode of 1 minus iota to the power 13

Answer 1

Step-by-step explanation:

your answer is here

in the last article,we learnt about iota which is a complex number equal to −1−−−√. Now, can we find power of iota (in) when n is any whole number. Lets simply calculate some of them and then I will define some general rule.

i=−1−−−√

i2=(−1−−−√)2=−1

i3=i×i2=i×−1=−i

i4=i2×i2=−1×−1=1

i5=i×i4=i×1=i

i6=i×i5=i×i=i2=−1

i7=i×i6=i×−1=−i

i8=(i2)4=(−1)4=1

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