MODEL 1
. 1. Find the following products:
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(a) (i) (x + y + 2z) (x2 + y² + 4z2 __XY – 2yz – 2zx)
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Step-by-step explanation:
Consider ( x + y + 2z ) ( x2 + y2 + 4z2 – xy – 2yz – 2zx ) = ( x + y + 2z ) [ x2 + y2 + ( 22 ) 2 – xy - y x 22 – 2z x x ] It is in the form of ( a + b + c ) ( a2 + b2 + c2 - ab - bc -ca ) = a3 + b3 + c3 - 3abc Hence ( x + y + 2z ) [ x2 + y2 + ( 22 ) 2 – xy - y x 22 – 2z x x ] = x3 + y3 + ( 22 ) 3 – 3 X X X y X 2z = x3 + y2 + 8z3 - 6xyz
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