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Math's Aryabhata
A copper wire of length 44 cm is to be bent into a square and a circle. Which will have a larger area?
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Answers
A copper wire of length 44 cm is to be bent into a square and a circle. Which will have a larger area?
Length of the Wire = 44 cm
➸ Area of the Circle = πr²
➸Area of the Square = a²
Circumference of the Circle = 2πr
44 = 2 × 22/7 × r
44*7/44 = r
r = 7 cm
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Now, Area of the circle = πr² = 22/7 × 7 × 7
= 22 × 7
= 154 cm²
Perimeter of the square = 44 cm
44 cm = 4 × side
44/4 = side
Side = 11 cm
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Now, Area of the square = a² = 11² = 121 cm²
Therefore, Circle's area is greater than the Area of the square.
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Answer:
Given :
- A copper wire of length 44 cm is bent into the shape of square and circle.
To Find :
- Which shape will have larger area ?
Solution :
_____________________
(Perimeter of square = Length of Wire) = 44cm
★ Length of each side of Square
=> 44/4 = 11
Therefore, Each side of Square is 11cm
★ Area of Square = Side × Side
=> 11 × 11 = 121cm²
Therefore, Area of Square is 121cm²
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(Circumference of Circle = Length of Wire) = 44cm
★ Radius of Circle :
=> Circumference / 2π
I Here, π = 22/7
=> 44 / 2π
=> 44 / ( 2 × 22/7 )
=> 44 / (1/2 × 7/22)
=> 7 cm
Therefore, Radius of Circle is 7cm
★ Area of Circle = πr²
=> 22/7 × (7)²
=> 22/7 × 49
=> 154cm²
Therefore, Area of Circle is 154cm²
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Hence, 154 > 121
So, Area of Circle is larger than the Area of Square.
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More Information:
★ Formulas of Area ★
Triangle = 1/2 × b × h
Circle = πr²
Square = (Side)²
Rectangle = L × B
Parallelogram = Base × Height