Math, asked by itzsehaj, 16 hours ago

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A copper wire of length 44 cm is to be bent into a square and a circle. Which will have a larger area?
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Answers

Answered by GalaxticKid
215

 \large \dag \sf \blue{ \underline{ \red{Question}}}

A copper wire of length 44 cm is to be bent into a square and a circle. Which will have a larger area?

 \large \dag \sf \red{ \underline{ \blue{Answer}}}

\sf\purple{\underline{Given:-}}

Length of the Wire = 44 cm

\sf\red{\underline{Formulas\::-}}

➸ Area of the Circle = πr²

➸Area of the Square = a²

\mathfrak\orange{Let's\:Find\:}

Circumference of the Circle = 2πr

44 = 2 × 22/7 × r

44*7/44 = r

r = 7 cm

_________________________

Now, Area of the circle = πr² = 22/7 × 7 × 7

= 22 × 7

= 154 cm²

Perimeter of the square = 44 cm

44 cm = 4 × side

44/4 = side

Side = 11 cm

_________________________

Now, Area of the square = a² = 11² = 121 cm²

Therefore, Circle's area is greater than the Area of the square.

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Answered by Anonymous
135

Answer:

Given :

  • A copper wire of length 44 cm is bent into the shape of square and circle.

To Find :

  • Which shape will have larger area ?

Solution :

_____________________

(Perimeter of square = Length of Wire) = 44cm

★ Length of each side of Square

=> 44/4 = 11

Therefore, Each side of Square is 11cm

★ Area of Square = Side × Side

=> 11 × 11 = 121cm²

Therefore, Area of Square is 121cm²

____________________

____________________

(Circumference of Circle = Length of Wire) = 44cm

★ Radius of Circle :

=> Circumference / 2π

I Here, π = 22/7

=> 44 / 2π

=> 44 / ( 2 × 22/7 )

=> 44 / (1/2 × 7/22)

=> 7 cm

Therefore, Radius of Circle is 7cm

★ Area of Circle = πr²

=> 22/7 × (7)²

=> 22/7 × 49

=> 154cm²

Therefore, Area of Circle is 154cm²

____________________

____________________

Hence, 154 > 121

So, Area of Circle is larger than the Area of Square.

____________________

More Information:

Formulas of Area

Triangle = 1/2 × b × h

Circle = πr²

Square = (Side)²

Rectangle = L × B

Parallelogram = Base × Height

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