Question

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Three consecutive integers are as such they are taken in increasing order and multiplied by 2, 3, and 4, respectively, they add up to 56. Find these numbers.
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Answer 1

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Answer:

It is given that the three consecutive integers multiplied by 2, 3, and 4 respectively, add up to 74. Therefore, the smallest consecutive integer out of the three numbers is 7. Therefore, the three consecutive integers are 7, 8, and 9.

Step-by-step explanation:

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Answer 2

$Let \: 3 \: Consecutive \: integers \\ : x , \: x+1 \: , \: x+2$

$As \: per \: Question$

$2x + 3(x + 1) + 4(x + 2) = 56$

$2x + 3x + 3 + 4x + 8 = 56$

$9x + 11 = 56$

$9x = 56 - 11$

$9x = 45$

$x = \frac{45}{9}$

$x = 5$

$x + 1 = 5 + 1 = 6$

$x + 2 = 5 + 2 = 7$

$Number \: are \: \: 5 , 6 \: and \: 7$