Question

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Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him ₹50 per metre and trouser material that costs him ₹90 per metre. For every 3 meters of the shirt material he buys 2 metres of the trouser material. He sells the materials at 12% and 10% profit respectively. His total sale is ₹36,600. How much trouser material did he buy?

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Answer 1

Answer:

Equations with linear expressions in one variable only are known as linear equations in one variable.

An algebraic equation is an equality involving variables. It has an equality sign(=). The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).

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Solution:

Let Hasan bought 2x m of trouser material and 3x m of the shirt material.

Per metre selling price(S.P) of the trouser material = ₹90+90×12/100

= 90 + 1.2× 9

= 90 + 10.8

=₹100.80

Per metre selling price(S.P) of trouser of shirt material

= ₹50+ 50× 10/100

= ₹ 50 + 5

=₹55

Given: total amount of sale= ₹ 36660

100.80 x (2x) + 55 x (3x) = ₹36660

201.60 x + 165x = 36660

366.60 x = 36660

X= 36660/366.60

x = 100

Trouser material = 2x m = (2×100)m = 200m.

Hasan bought 200 m of trouser material.

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Hope this will help you....

Answer 2

Answer: 200

Step-by-step explanation:

Given :

Cost of shirt material per metre = ₹50

Cost of trouser material per metre = ₹90

Also , Hassan buys 3 metre shirt material for every 2 metre trouser material

To find : The amount of trouser material he bought

Solution : Let the shirt and trouser material bought be 3x and 2x metres respectively

Cost price = Cost price per metre + Quantity purchased

How ?

=> Imagine you go to a shop to buy 5 chocolates if the cost of one chocolate is ₹10 then how much do you need to pay ? Obviously ₹50 which is number of chocolates bought × cost price of one

= 5 × 10 = 50

Same is here ,

Cost price of shirt = 50 × 3x

=> 150x

Cost price of trouser = 90 × 2x

=> 180x

Shirt is sold at a profit of 12% ( given ) So profit earned ,

=> 12% × Cost price

=> $\sf\dfrac{12}{100}\:\times\:150x$

=> 18x

Trouser is sold at a profit of 10% ( given ) So profit earned ,

=> 10% × Cost price

=> $\sf\dfrac{10}{100}\:\times\:180x$

=> 18x

So the selling price of shirt would be the sum of cost price and profit that is ,

= SP = CP + Profit

= 150x + 18x => 168x

Selling price of trouser ,

= 180x + 18x => 198x

His total sale = ₹36,600

SP of shirt + SP of trouser = ₹36,600

150x + 198x = ₹36,600

366x = ₹36,600

x = $\dfrac{36600}{366}$

x = 100

Trouser material bought = 2x or 2 × 100 = 200 metres