Question

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STD:-VIII
$\huge{ \purple{ \fbox{question:-}}}$
i)​Y³-27
ii)X³-64​

Answer 1

i) Y³-27

$\boxed{\tt \: Used \: Identity }$

$\bf ⟶ \red{{a}^{3} - {b}^{3} = (a - b)( {a}^{2} + {b}^{2} + ab)}$

$\bf {y}^{3} - 27$

$\tt = ( {y})^{3} - (3) ^{2}$

$\tt = (y - 3) \: \: \: [ (y) ^{2} + (3)^{2} + (y) \times (3) ]$

$\tt = (y - 3)( {y}^{2} + 9 + 3y)$

ii) x³-64

$\boxed{\tt \: Used \: Identity }$

$\bf ⟶ \red{{a}^{3} - {b}^{3} = (a - b)( {a}^{2} + {b}^{2} + ab)}$

$\bf \: x ^{3} - 64$

$\tt = ( {x})^{3} - (4) ^{3}$

$\tt = (x - 4) \: \: \: [ (x) ^{2} + (4)^{2} + (x) \times (4) ]$

$\tt = (x - 4) (x^{2} + 16 + 4x)$