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The kinetic energy of an object of mass m, moving with a velocity of 5 m/s is 25 J. What will be its kinetic energy when its speed is doubled? it is given here doubled not tripled
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Hence, kinetic energy = 25 × 4 = 100 J. (ii) If velocity is increased three times, then its kinetic energy becomes 9 times the original value, because it is proportional to the square of the velocity. Hence, kinetic energy = 25 × 9 = 225 J.
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Kinetic Energy is 100J when it is doubled
kinetic energy is 225J when it is increased three times
Explantion
V = 5m/s
KE = 25J
KE = 1/2MV^2
25 = 1/2 × M × 5 × 5
2 = m
When velocity is doubled
V = 5×2 = 10 m/s
KE = 1/2 × 2 × 10 × 10
KE = 100 J
When velocity is increased three times
V = 5×3 = 15m/s
KE = 1/2 × 2 × 15 × 15.
KE = 225 J
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