Question

❍ Moderators
❍ Brainly star
❍ Other best users

STD-VIII
Chp-6 Factorisation Of Algebraic Expressions
1)Factorise:
$1) {5y}^{2}+5y-10 \\ 2)44 {x}^{2} - x - 3$
​

Answer 1

Answer :-

$1) \: 5 {y}^{2} + 5y - 10 = 0$

$by \: splitting \: the \: middle \: term$

$5 {y}^{2} + 10y - 5y \: - 10 = 0$

$5y \: (y + 2) - 5(y + 2) = 0$

$(5y - 5)(y + 2) = 0$

$(5y - 5) = 0 \\ 5y = 5 \\ y \: = 1$

$(y \: + 2) = 0 \\ y = - 2 \: (neglect \: )$

___________________________________

$2) \: 44 {x}^{2} - x - 3 = 0$

$by \: splitting \: the \: middle \: term \:$

$44 {x}^{2} + 11x - 12x - 3 = 0$

$11x \: (4x + 1) - 3(4x + 1) = 0$

$(11x - 3)(4x + 1) = 0$

$(11x - 3) = 0 \\ 11x \: = 3 \\ x \: = \frac{3}{11}$

$(4x \: + 1) = 0 \\ 4x \: = - 1 \\ x \: = \frac{ - 1}{4} ( \: neglect \: )$

Answer 2

In the given polynomial 5y

2

+5y−10,

The first term is 5y

2

and its coefficient is 5.

The middle term is 5y and its coefficient is 5.

The last term is a constant term −10.

Multiply the coefficient of the first term by the constant 5×−10=−50.

We now find the factor of −50 whose sum equals the coefficient of the middle term, which is 5 and then factorize the polynomial 5y

2

+5y−10 as shown below:

5y

2

+5y−10

=5y

2

−5y+10y−10

=5y(y−1)+10(y−1)

=(5y+10)(y−1)=5(y+2)(y−1)

Hence, 5y

2

+5y−10=5(y+2)(y−1).

Thank u for the points

May god bless u ☺️