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⚘If three point masses m¹,m² and m² are situated at the vertice of an equilateral triangle of side a, then what will be the co-ordinates of the centre of mass of this system
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Answer 1

Here you go

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Answer 2

Answer:

Moment of inertia is the product of mass and square of separation between particle and axis of rotation.

e.g, M.I = mr².

Here, we see, separation of mass m1 and altitude NN′ is 0.

alteration between mass m2 and NN ′ is (a/2) also for m3 separation is (a/2).

Moment of inertia about altitude passing through m1 = I1 + I2 + I3

where I1, I2 and I3 where I are M.I of m1, m2 and m3 respectively.

M. I = m1.(0) + m2 × (a/2)² + m3 × (a/2)²

$= \frac{a {}^{2} }{4 \times (m2 \: + \: m3} ).$