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Answers
Option a
Step-by-step explanation:
Solution :-
Given that
AB || CD
< BOA = 108°
< COD = 120°
Now,
Draw a parallel line EF to AB and CD through O
AB || EF and OA is a transversal then
<BAO + < EOA = 180°
Since the interior angles on the same side to the transversal are supplementary.
=> 108° +< FOA = 180°
=> < FOA = 180°-108°
=> < FOA = 72° -------(1)
and
EF || CD and OC is a transversal then
< DCO + < FOC = 180°
Since the interior angles on the same side to the transversal are supplementary
=> 120°+<FOC = 180°
=> < FOC = 180°-120°
=> < FOC = 60° -------(2)
On adding (1)&(2) then
=> < FOA + < FOC = 72°+60°
=> < FOA + < FOC = 132°
=> < AOC = 132°
Therefore, < AOC = 132°
Answer:-
The measure of < AOC = 132°
Used formulae:-
→ The interior angles on the same side to the transversal are supplementary
REFER TO THE ATTACHMENT!
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