Question

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Answer 1

l1 ‖ l2 and l3 is transversal

∠1 = 3x (Vertically opposite angle)

y = ∠1 (Corresponding angle)

y = 3x (i) y + x = 180°(Linear pair)

3x + x = 180°[From (i)]

4x = 180°

x = 45°

Therefore, y = 3x = 3 x 45°

= 135°

OR

ANSWER

$\begin{gathered}y = 3x \: \: \:(alternate \: angles) \\ also \\ x \: and \: y \: are \: linear \: pairs \\ = > x + y = 180 \\ x + 3x = 180 \\ 4x = 180 \\ = > x = \frac{18 0}{4} \\ = > x = 45\end{gathered}$

$\begin{gathered}\large\blue{= > \:y\:=\:3x\:=\:3×45\:=\:135} \\ \end{gathered}$

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Answer 2

l1 ‖ l2 and l3 is transversal

∠1 = 3x (Vertically opposite angle)

y = y = ∠1 (Corresponding angle)

y = 3x ()

y + x = 180°(Linear pair)

3x + x = 180°[From (i)]

4x = 180° x = 45°[From ]

4x = 180° x = 45° Therefore, y = 3x = 3 x

45° = 135°